ICSE Class 10 Answered
Explain the oxidising property of sulphuric acid on non-metals, metals and inorganic compounds by giving one example for each.
Asked by Topperlearning User | 21 Apr, 2016, 10:28: AM
Expert Answer
The oxidising property of sulphuric acid can be explained as follows:
a. Non-metals
C + 2H2SO4 → CO2 + 2H2O +2SO2
S + 2H2SO4 → 2H2O +3SO2
b. Metals
Cu + 2H2SO4 → CuSO4 + 2H2O +SO2
Zn + 2H2SO4 → ZnSO4 + 2H2O +SO2
c. Inorganic compounds
2HBr + H2SO4 →Br2 + 2H2O + SO2
H2S + H2SO4 → S + 2H2O + SO2
(Write any one example for each)
Answered by | 21 Apr, 2016, 12:28: PM
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