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ICSE Class 10 Answered

Explain the oxidising property of sulphuric acid on non-metals, metals and inorganic compounds by giving one example for each.
Asked by Topperlearning User | 21 Apr, 2016, 10:28: AM
answered-by-expert Expert Answer

The oxidising property of sulphuric acid can be explained as follows:

a.       Non-metals

               C + 2H2SO4 → CO2 + 2H2O +2SO2

                S + 2H2SO4 → 2H2O +3SO2

b.      Metals

                Cu + 2H2SO4 → CuSO4 + 2H2O +SO2

                 Zn + 2H2SO4 → ZnSO4 + 2H2O +SO2

c.       Inorganic compounds

                2HBr + H2SO4 →Br2 + 2H2O + SO2

                H2S + H2SO4 → S + 2H2O + SO2

(Write any one example for each)

Answered by | 21 Apr, 2016, 12:28: PM
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