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ICSE Class 9 Answered

evaluate e v a l u a t e space cube root of left parenthesis square root of 7 to the power of 4 end root end root right parenthesis to the power of 6 space end exponent cross times root index 6 of left parenthesis square root of 7 to the power of 8 right parenthesis cubed end root
Asked by nandanam2020 | 15 Jun, 2019, 07:36: PM
answered-by-expert Expert Answer
cube root of open parentheses square root of 7 to the power of 4 end root close parentheses to the power of 6 end root cross times root index 6 of open parentheses square root of 7 to the power of 8 end root close parentheses cubed end root
equals cube root of open parentheses 7 squared close parentheses to the power of 6 end root cross times root index 6 of open parentheses 7 to the power of 4 close parentheses cubed end root
equals cube root of open parentheses 7 to the power of 12 close parentheses end root cross times root index 6 of open parentheses 7 to the power of 12 close parentheses end root
equals 7 to the power of 4 cross times 7 squared
equals 7 to the power of 6
Answered by Renu Varma | 16 Jun, 2019, 12:06: AM
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