CBSE Class 9 Answered
Evaluate (999)3.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
(999)3 = (1000 - 1)3
(a - b)3 = a3 - b3 - 3a2b + 3ab2
(999)3
= (1000)3 - (1)3 - 3 (1000)2 
1 + 3 1000 12
= 1000000000 - 1 - 3000000 + 3000
= 997000000 + 3000 - 1 = 997002999
Answered by | 04 Jun, 2014, 03:23: PM
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