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NEET Class neet Answered

Equivalent weight is 
question image
Asked by Mrinal | 20 May, 2019, 10:07: PM
answered-by-expert Expert Answer
Option (3) is correct.
 
Given:
 
Molecular weight of Na2S2O3 = M
 
The reaction is,
 
Na2S2O3 + H2O + Cl2  →Na2SO4 + 2HCl  + S
 
The change in oxidation number for,
 
Na2S2O3 → Na2SO is
 
+2 → +6  = 4
 
For , Na2S2O3 → S
 
+2 → 0 = 2
 
We know,
 
Equivalent weight is,
 
equals space fraction numerator Molecular space weight space over denominator Change space in space oxidation space number end fraction

equals bevelled fraction numerator straight M over 4 plus straight M over 2 over denominator 2 end fraction

equals fraction numerator 3 straight M over denominator 8 end fraction
 
The equivalent weight of  Na2S2O3  is  fraction numerator 3 straight M over denominator 8 end fraction.
Answered by Varsha | 21 May, 2019, 10:45: AM
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