Equal volumes of two solutions with pH values 8 and 10 are mixed together.The pH of resulting solution is:
pH = 8 means [OH-] = 10-8 hence [H+] = 10-6 .
pH= 10 means [OH-] = 10-10 hence [H+] = 10-4 .
M1V1 + M2V2= Mx 2V
10-6 x V + 10-4 x V = M x 2V
10-4 ( 10-2 + 1) V/2V = M
10-4 ( 0.01 + 1)/2 = M
10-4 ( 1.01 )/2 = M
M= 0.505 x 10-4.
pH = -log[H+]
pH = 4 - log[0.505]
pH= 4 - (-0.296)
pH = 4.26
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