Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

during an experiment ,an ideal gas is found to obey an additional law vp2=constant.the gas is initially at a temp T & volume V .when it expands to a volume 2v ,what becomes the value of temp? state 2 conditions for a gas to be ideal?
Asked by Riya Rose | 03 Mar, 2014, 05:49: AM
answered-by-expert Expert Answer

The description of experiment is not very clear.

The relationship is given between pressure and volume, PV2= constant.

The initial state of gas is given in terms of temp. T and volume V.

It is required to find at what temperature does the gas expand to twice the original volume?

Please clarify your question. 

The ideal gas law neglects both molecular size and intermolecular attractions.

When density of a gas is low (larger volumes at lower pressures), the average distance between nearby molecules increases compared to molecular size.

When a gas is at high temperature the molecules are farther apart. The importance of intermolecular attractions decreases.

Therefore, two conditions for a gas to follow the ideal gas law: high temperatures and low pressures.

Answered by | 03 Mar, 2014, 12:30: PM
CBSE 11-science - Physics
Asked by pratikshyadashrkl | 01 May, 2020, 10:24: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Madhurimaurya609 | 11 Jul, 2018, 08:14: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 11 May, 2015, 01:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 11 May, 2015, 02:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×