CBSE Class 12-science Answered
Nature of the paths executed by the charged particle moving in a uniform magnetic field will be:
i) If the charged particle is moving parallel to the direction of, it does not experience any force, because angle θ between and is 0º or 180º and
F= qvBsin0= 0.
So, the particle will continue to move along the straight line.
ii) If charged particle is moving perpendicular to , it experiences maximum force F= qvBsin90º= qvB.
So, this force will provide the required centripetal force and the charged particle will describe a circular path of radius r i.e
mv2/r= qvB.
If the charged particle is moving in the magnetic field such that its velocity makes angle θ with the direction of , the particle will move under the combined effect of velocity components i.e vcosθ and vsinθ. So, the particle will cover linear, as well as circular path i.e the path will be helical.