CBSE Class 11-science Answered

The description can be written compactly as,

F μ^a R^b V^c , where symbols have their usual meaning.  ............(1)

The dimensions are,

F = [MLT^-2]

μ  =[ML^-1T^-1]

R = [L]

V = [LT^-1]

Using these dimensions in (1),

[MLT^-2] = [ML^-1T^-1]^a [L]^b [LT^-1]^c

Comparing dimensions of M:

1 = a

Comparing dimensions of L:

1 = - a + b +c

b+c = 2          .. since a = 1,

Comparing dimensions of T:

-2 = -a -c

c = 1,

Hence b = 1.

Therefore the relation is,

F  μ R V ,

F = C μ R V .

where C is some constant.

regards,

Team,

TopperLearning.