CBSE Class 11-science Answered
Determine the total energy per unit mass possessed by water at a point, where pressure is 196x103 N/m2, velocity is 0.2 m/s and height of water level from the ground is 0.40 m.
Asked by Topperlearning User | 31 Jul, 2014, 04:34: PM
Expert Answer
P = 196 x 103 N/m2
ρ = 103 Kg/m3
h = 0.40 m
v = 0.2 m/s
(i) Pressure energy per unit mass= P/ρ = 196 x 103/103 = 196 J/Kg
(ii) Kinetic energy per unit mass = ½ v2 = 1/2 x (0.2)2 = 0.02 J/Kg
(iii) Gravitational potential energy per unit mass = gh = 9.8 x 0.4 = 3.92 J/Kg
(iv) Total energy per unit mass = P/ρ + ½ v2 + gh
= (196 + 0.02 + 3.92) J/Kg
= 199.94 J/Kg
Answered by | 31 Jul, 2014, 06:34: PM
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