CBSE Class 12-science Answered

Given:

[N₂O₅]                      Initial rate

0.093                      4.84 x 10^{-4   --------- (1)}

0.184                      9.37 X 10^{-4   ---------(2)}

0.224                      1.16 x 10^{-3  ---------(3)}

From equation (1) and (2), it is observed that when the concentration of [N₂O₅] doubles the rate is also doubled.

Also, from equation (1) and (3) it is observed that when the concentration of [N₂O₅] triple the rate is also tripled.

Therefore, 

Rate =k[N₂O₅]

k = 5.2×10^-3 s^-1 

Rate law:

Rate =5.2×10^-3 s^-1 [N₂O₅]