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Home / Doubts and Solutions/JEE/Mathematics

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Asked by g_archanasharma 16th December 2018, 6:19 PM
Answered by Expert
Answer:
begin mathsize 16px style 8 to the power of 1 plus open vertical bar cosx close vertical bar plus open vertical bar cos squared straight x close vertical bar plus open vertical bar cos cubed straight x close vertical bar plus.... end exponent equals 4 cubed Put space open vertical bar cosx close vertical bar equals straight m 8 to the power of 1 plus straight m plus straight m squared plus straight m cubed plus..... end exponent equals 64 Log subscript 8 space 8 to the power of fraction numerator 1 over denominator 1 minus straight m end fraction end exponent equals Log subscript 8 8 squared fraction numerator 1 over denominator 1 minus straight m end fraction equals 2 1 minus straight m equals 1 half straight m equals 1 half open vertical bar cosx close vertical bar equals 1 half cosx equals plus-or-minus 1 half Find space general space solution space of space this space equation. Find space the space interval space using space general space solution space of space the space equation. end style
Answered by Expert 17th December 2018, 10:18 AM
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