Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

9:00am - 9:00pm IST all days.

Business Inquiry (North)

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

022-62211530

Mon to Sat - 10 AM to 7 PM

Detailed solution for this.

qsnImg
Asked by g_archanasharma 18th December 2018, 7:31 PM
Answered by Expert
Answer:
begin mathsize 12px style open parentheses x minus 3 close parentheses cubed plus 1 space equals space 0
L e t space y space equals space x minus 3 space semicolon space t h e n space w e space h a v e space space space y cubed plus 1 space equals space 0

y cubed space equals space minus 1 space equals space cos left parenthesis 2 k plus 1 right parenthesis straight pi space plus space straight i space sin open parentheses 2 straight k plus 1 close parentheses straight pi space space comma space straight k space equals space 0 comma 1 comma 2
straight y space equals space open parentheses cos left parenthesis 2 straight k plus 1 right parenthesis straight pi space plus space straight i space sin open parentheses 2 straight k plus 1 close parentheses straight pi close parentheses to the power of bevelled 1 third end exponent space equals space open parentheses cos space fraction numerator left parenthesis 2 straight k plus 1 right parenthesis straight pi over denominator 3 end fraction space plus space straight i space sin space fraction numerator left parenthesis 2 straight k plus 1 right parenthesis straight pi over denominator 3 end fraction close parentheses space comma space straight k space equals 0 comma space 1 comma space 2

when space straight k space equals space 0 comma space straight y space equals space open parentheses cos space straight pi over 3 space plus space straight i space sin space straight pi over 3 close parentheses space equals space 1 half plus straight i fraction numerator square root of 3 over denominator 2 end fraction
when space straight k space equals 1 comma space straight y space equals space open parentheses cos space straight pi space plus space straight i space sin space straight pi close parentheses space equals space minus 1
when space straight k equals 2 comma space straight y space equals space open parentheses cos space fraction numerator 5 straight pi over denominator 3 end fraction space plus space straight i space sin space fraction numerator 5 straight pi over denominator 3 end fraction close parentheses space equals space 1 half minus straight i fraction numerator square root of 3 over denominator 2 end fraction end style
 
since y = (x-3), sum of complex roots  = begin mathsize 12px style 3 plus 1 half plus i fraction numerator square root of 3 over denominator 2 end fraction plus 3 plus 1 half minus i fraction numerator square root of 3 over denominator 2 end fraction space equals space 7 end style
Answered by Expert 19th December 2018, 1:49 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp