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Asked by g_archanasharma | 04 Apr, 2019, 08:43: AM
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f(x) = x3 - x  and Φ(x) = sin2x
 
(a) f(2) = 8 -2 = 6,  Φ(6) = sin12 ≠ sin2
 
(b) f(1) = 1- 1 = 0, Φ(0) = sin0 = 0  ≠ 1
 
(c) Φ(π/12) = sin(π/6) = 1/2  ;   f(1/2) = (1/8) - (1/2) = -3/8
 
(d) f(1) = 0, f(f(1) = 0 ≠ 2
Answered by Thiyagarajan K | 04 Apr, 2019, 10:21: AM

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