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Asked by g_archanasharma | 20 Feb, 2019, 05:23: PM

Expert Answer

Option (2) is correct.

Combustion of carbon:

straight C space space plus space space straight O subscript 2 space rightwards arrow space CO subscript 2 space space space space space increment straight H subscript 1 space equals space minus 394 space kJ divided by mol Combustion space of space Carnon space monoxide colon CO space space plus space bevelled 1 half straight O subscript 2 space rightwards arrow space CO subscript 2 space space space increment straight H subscript 2 space equals space minus 285 space kJ divided by mol Formation space of space carbon space monoxide colon straight C space plus space bevelled 1 half straight O subscript 2 space space space rightwards arrow space CO space space space increment straight H space equals ? increment straight H space equals space increment straight H subscript 1 space minus increment straight H subscript 2 space space space space space space space space equals space minus 394 space minus open parentheses negative 285 close parentheses increment straight H space space equals open parentheses negative 109 close parentheses space kJ divided by mol

The heat of formation of CO is -109 kJ/mol.

Answered by Varsha | 21 Feb, 2019, 11:16: AM

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