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CBSE Class 11-science Answered

Derive third law of motion by using the law of conservation of linear momentum  
Asked by vasudevdewangan031 | 07 Mar, 2019, 07:50: PM
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Consider two bodies A and B, with initial momenta pA and pB. The bodies collide, get apart, with final momenta p′ A and p′ B
respectively.   If in collision  force exerted by A on B is FAB and the reaction force exerted by B on A is FBA , then by second law we have
 
FAB Δt  = p'A  - pA   .............................(1)
 
and   FBA Δt  = p'B  - pB    .............................(2)
 
we have considered that colission time Δt is same for both the bodies.
 
By Conservation of momentum, we have,    pA + pB  = p'A + p'B  or   p'A - pA  =  - (p'B - pB )  .................(3)
 
from eqns. (1), (2)  and (3),  we  get   FAB = - FBA  , which is newtons third law
Answered by Thiyagarajan K | 08 Mar, 2019, 09:11: AM
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