CBSE Class 9 Answered
Derive the third equation of motion v2 - u2 = 2as using velocity-time graph.
Asked by Topperlearning User | 16 Jun, 2016, 05:04: PM
Expert Answer
Consider the velocity-time graph for a body having some non zero initial velocity at time t = 0.
u: velocity at time t1
v: velocity at time t2
a: uniform acceleration of the body along the straight line
Displacement covered during the time interval t2 - t1 = Area ABt1t2
S = Area of triangle ABA’ + Area of rectangle AA’t2t1 = Area of trapezium
S = ½ x Sum of parallel sides x Perpendicular distance
....... (Equation 1)
From the first equation of motion, v = u + at;
Substituting in equation 1, we get
or, v2 – u2 = 2as
which is the required equation of motion.
Answered by | 16 Jun, 2016, 07:04: PM
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