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CBSE Class 9 Answered

Derive the third equation of motion v2 - u2 = 2as using velocity-time graph.
Asked by Topperlearning User | 16 Jun, 2016, 05:04: PM
answered-by-expert Expert Answer

Consider the velocity-time graph for a body having some non zero initial velocity at time t = 0.

u: velocity at time t1
v: velocity at time t2
a: uniform acceleration of the body along the straight line

Displacement covered during the time interval t2 - t1 = Area ABt1t2
S = Area of triangle ABA’ + Area of rectangle AA’t2t1  = Area of trapezium
S = ½  x Sum of parallel sides x Perpendicular distance
begin mathsize 12px style straight s equals 1 half open parentheses straight v plus straight u close parentheses straight t end style ....... (Equation 1)
From the first equation of motion, v = u + at; 

begin mathsize 12px style straight t equals fraction numerator straight v minus straight u over denominator straight a end fraction end style

Substituting in equation 1, we get 
begin mathsize 12px style straight s equals 1 half open parentheses straight v plus straight u close parentheses fraction numerator open parentheses straight v minus straight u close parentheses over denominator straight a end fraction end style
or,  v2 – u2 = 2as
which is the required equation of motion.

Answered by | 16 Jun, 2016, 07:04: PM
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