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derive the relationship between Kp and Kc for folowing reaction.

aA+bB.....>cC+dD

Asked by futureisbright051101 28th February 2018, 12:14 PM
Answered by Expert
Answer:
The relation between kp and Kc is,
 
bold A bold space bold gaseous bold space bold reaction bold space bold consists bold space bold of bold space bold particle bold space bold gaseous bold space bold species bold space bold which bold space bold exert bold space bold an bold space bold individual bold space bold pressure bold comma bold space bold called bold space bold as bold space bold partial bold space bold pressure bold space
bold which bold space bold is bold space bold taken bold space bold into bold space bold account bold space bold for bold space bold the bold space bold measure bold space bold of bold space bold the bold space bold equilibrium bold space bold constant bold space bold called bold space bold Kp bold.
bold space bold Consider bold space bold gaseous bold space bold reaction bold comma

bold nA bold left parenthesis bold g bold right parenthesis bold space bold plus bold space bold mB bold left parenthesis bold g bold right parenthesis bold space bold space bold space bold rightwards harpoon over leftwards harpoon bold space bold space bold space bold aY bold left parenthesis bold g bold right parenthesis bold space bold plus bold space bold bZ bold left parenthesis bold g bold right parenthesis

bold where bold comma
bold space bold PA bold equals bold partial bold space bold pressure bold space bold of bold space bold A
bold space bold PB bold equals bold space bold partial bold space bold pressure bold space bold of bold space bold B
bold space bold PY bold equals bold space bold partial bold space bold pressure bold space bold of bold space bold Y
bold space bold PZ bold equals bold partial bold space bold pressure bold space bold of bold space bold Z bold space bold space bold space
 
Answered by Expert 28th February 2018, 3:44 PM
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