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CBSE Class 11-science Answered

Derive the equation above. 
Asked by Vineeth K | 05 Apr, 2016, 07:51: AM
answered-by-expert Expert Answer
begin mathsize 14px style The space total space force space straight F space produces space an space acceleration space straight a space on space the space system.
Hence comma space this space acceleration space is
straight a equals straight F over straight m equals fraction numerator straight F over denominator straight m subscript 1 plus straight m subscript 2 plus straight m subscript 3 end fraction
Now comma space the space force space straight F subscript 1 space on space mass space straight m subscript 1 space has space to space balance space the space remaining space two space boxes
in space order space to space remain space in space contact.
So comma space we space have
straight F subscript 1 equals open parentheses straight m subscript 2 plus straight m subscript 3 close parentheses straight a
straight F subscript 1 equals fraction numerator straight m subscript 2 plus straight m subscript 3 straight F over denominator straight m subscript 1 plus straight m subscript 2 plus straight m subscript 3 end fraction end style
Answered by Romal Bhansali | 05 Apr, 2016, 11:49: AM
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