Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Derive an expression for displacement in the last or nth second 

Asked by Paitboy23 26th June 2019, 5:44 AM
Answered by Expert
Answer:
Let u be the initial velocity and a is acceleration.
 
--------------------------------------------------------------------------------------------------------------
To get velecity V after T seconds we use the formula, V = U+A×T , where A is acceleration
----------------------------------------------------------------------------------------------------------------
 
Hence velocity after (n-1) seconds = u+(n-1)×a .........................(1)
 
------------------------------------------------------------------------------------------------------------
To get displacement S after T seconds, we use the formula,  S = U×T + (1/2)×A×T2 ,
where U is initial velocity and A is acceleration
------------------------------------------------------------------------------------------------------------
 
Hence displacement Sn at nth or last second is obtained by using the intial velocity from eqn.(1) and it is given by,
 
Sn = u+(n-1)×a +(1/2)×a×1 = u+a×[ n- (1/2) ]
Answered by Expert 26th June 2019, 11:06 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp