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CBSE - XI Science - Physics - Motion in a Straight Line

dear sir/mam, plz answer the following question....

Asked by 28th February 2008, 12:42 AM
Answered by Expert



Dear sir/mam, plz answer the following question....

a particle moves such that its position vector 'r' at time 't' is given by-


   r    = i(3t2+2t)+ j(2t2+4t)

determine the magnitude of (i)velocity at t=5sec


(where i and j are unit vectors along X and Y-axis)


The velocity v = (d/dt ) . (i(3t2+2t)+ j(2t2+4t)

which on differentiating, we get,

v = (6t+2)i+(4t+4)j

substituting for t = 5 s

we get,

v=32i+24j  m/s

Do similar thing to find acceleration given by a = (d/dt)v




Answered by Expert 8th December 2017, 3:03 PM

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Tags: Acceleration
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