Could you please solve this numerical!!
Asked by pukai7229
10th July 2018,
8:08 PM
Answered by Expert
Answer:
Fig(a) shows when 10g block is resting on table.
on the block m1 acting forces are W1 due to its own weight and Tension T in the string.
At Equilibrium W1 = T or T = 30×10-3 ×9.8 = 0.294 N
on the block m2 acting forces are W2 due to its own weight, Tension in the string and applied force F.
At equilibrium W2 + F = T or F = T - W2 = 0.294 - 10×10-3 × 9.8 = 0.196 N
--------------------------------
Fig.(b) shows when the force is released so that the blocks are in acceleration.
On the block m1, now the net force F1 acting on it is given by, F1 = ( W1 - T ) ...........(1)
let m1 is moving downwards with acceleration a, then we have F1 = m1 × g - T = m1 × a ...........(2)
On the block m2, the acting forces are W2 and T . Block m2 moves upward with acceleration a
hence, we write T - m2 × g = m2 × a ................................(3)
adding (2) and (3), we get, (m1 - m2 )×g = (m1 + m2 )×a or 
Tension T will be obtained from (3) , T = m2×(a+g) = 10×10-3×(4.9+9.8) = 0.147 N
Answered by Expert
13th July 2018,
2:27 PM
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