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Home / Doubts and Solutions/JEE/Mathematics

Cos^2(48)-sin^2(12)=?

Asked by jaychandran1967 8th December 2017, 1:16 PM
Answered by Expert
Answer:
begin mathsize 16px style cos squared 48 degree minus sin squared 12 degree equals cos squared 48 degree minus sin squared left parenthesis 90 degree minus 78 degree right parenthesis equals cos squared 48 degree minus cos squared 78 degree equals left parenthesis cos 48 plus cos 78 right parenthesis left parenthesis cos 48 minus cos 78 right parenthesis Using space cosC plus cosD equals 2 cos open parentheses fraction numerator straight C plus straight D over denominator 2 end fraction close parentheses cos open parentheses fraction numerator straight C minus straight D over denominator 2 end fraction close parentheses and space cosC minus cosD equals 2 cos open parentheses fraction numerator straight C plus straight D over denominator 2 end fraction close parentheses cos open parentheses fraction numerator straight D minus straight C over denominator 2 end fraction close parentheses Simplify space it space further space you space will space get space 1 half cos 36 degree rightwards double arrow 1 half cross times fraction numerator square root of 5 plus 1 over denominator 4 end fraction equals fraction numerator square root of 5 plus 1 over denominator 8 end fraction end style
Answered by Expert 8th December 2017, 4:38 PM
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