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3Cu(NO3 )2 + 2NO + 4H2O

If 18.75 g Cu(NO3 )2 is eventually obtained, then how many grams of nitric oxide (NO) would have also formed according to the preceeding equation. (At mass of Cu = 63)

A) 2g B) 4g C) 6g D) 8g
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# Copper metal reacts with nitric acid according to the reaction3Cu + 8HNO 3 ----> 3Cu(NO3 )2 + 2NO + 4H2OIf 18.75 g Cu(NO3 )2 is eventually obtained, then how many grams of nitric oxide (NO) would have also formed according to the preceeding equation. (At mass of Cu = 63)A) 2g B) 4g C) 6g D) 8g

Asked by sureshkalanjoor 7th December 2015, 6:05 PM

The correct answer option is A) 2 g.

189 g (3x63) Cu gives 562.68 g (3x187.56)Cu(NO3)2

Hence, 18.75 g of Cu(NO3)2 can be obtained from 6.30 g Cu.

Now, 189 g of Cu gives 60.02 g (2x30.01)NO

Hence, 6.3 g Cu gives 2 g NO.

Answered by Expert 7th December 2015, 7:14 PM
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