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CBSE Class 9 Answered

construct triangle PQR in which QR = 7 cm, angle Q = 45 degree and PQ - PR = 2 cm.
Asked by Aravindh Ramesh | 07 Jan, 2014, 07:35: PM
answered-by-expert Expert Answer
Following steps will be followed to draw the required triangle
 
Step I: Draw the line segment QR = 7 cm and at point Q make an angle of 45° say angle XQR.    

Step II: Cut the line segment QD = 2 cm (equal to PQ – PR) on ray QX.

Step III: Join DR and draw the perpendicular bisector DR.

Step IV: Let it intersect QX at point P. Join PR. PQR is the required triangle.
Answered by | 07 Jan, 2014, 11:15: PM

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