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CBSE Class 11-science Answered

Construct the Born-Haber cycle.
Asked by Topperlearning User | 14 Aug, 2014, 01:20: PM
answered-by-expert Expert Answer

Born-Haber cycle is diagram for determining lattice enthalpies. Here we are going to construct this diagram for Sodium chloride NaCl.

 
       
Answered by | 14 Aug, 2014, 03:20: PM

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CBSE 11-science - Chemistry
Que: Differentiate between enthalpy and entropy??
Asked by advssdrall | 11 Jan, 2022, 07:44: PM
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CBSE 11-science - Chemistry
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Asked by adityasolanki7773 | 22 Oct, 2020, 03:40: PM
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CBSE 11-science - Chemistry
a steel fiber is in a oxygen filled container which is closed with a frictionless piston. the iron in the steel fiber reacts with oxygen to form Fe2O3 , the heat generated by the reaction is removed during the process to maintain the temperature constant which is 25 degrees centigrade. for the reaction of 2 moles of iron 831.08KJ of heat is removed. calculate the heat , work and internal energy of change of the system
Asked by pranavisrihari | 08 Sep, 2020, 05:24: PM
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CBSE 11-science - Chemistry
How to solve this Question?
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Asked by varakalasuchi3 | 28 Mar, 2020, 04:47: PM
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CBSE 11-science - Chemistry
When 100ml of strong acid mixed with 100ml of strong base, change in temperature is 5°c. Determine the change in temperature when 10ml of strong acid mixed with strong base.
Asked by patra04011965 | 09 Nov, 2019, 12:18: PM
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CBSE 11-science - Chemistry
Please answer
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Asked by prakriti12oct | 27 Sep, 2019, 01:43: AM
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CBSE 11-science - Chemistry
How is isothermal irreversible expansion cyclic  and how is delta H=0 for the process?
Asked by prakriti12oct | 26 Sep, 2019, 01:40: AM
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CBSE 11-science - Chemistry
The transition Sn(s, gray) ⇌ Sn(s, white) is in equilibrium at 18°C and 1 atm pressure. If ΔS = 8.811K mol for the transition at 18°C and if the densities are 5.75 g/cm3 for gray tin and 7.28 g/cm3 for white tin, calculate the transition temperature under 100 atm pressure
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Asked by sayantan.chem2 | 06 Aug, 2019, 05:07: PM
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CBSE 11-science - Chemistry
6.63 sum
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Asked by lovemaan5500 | 21 Jan, 2019, 06:37: AM
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CBSE 11-science - Chemistry
One mole of anhydrous MgCl2 dissolves in water and librates 25 cal/mol of heat. ∆Hhydration of MgCl2 = –30 cal/mol. Heat of dissolution of MgCl2.7H2O(s) is :- (1) +5 cal/mol (2) –5 cal/mol (3) 55 cal/mol (4) –55 cal/mol
Asked by Atulcaald | 25 May, 2018, 12:24: AM
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