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Construct an equilateral triangle whose altitude is 4.5cm.

Asked by araima2001 6th March 2015, 3:08 PM
Answered by Expert
Answer:

Draw a line PQ.

Take any point L on this line.

Construct perpendicular AL on PQ.

Cut a line segment AD from D equal to 4.5 cm.

Make angles equal to 30° at A on both sides of AD, say ∠CAD and ∠BAD where B and C lie on XY.

Then, ABC is the required triangle.

Justification:

Since ∠A = 30° + 30° = 60° and AL ⊥ BC,

Therefore, ∆ABC is an equilateral triangle with altitude AL = 4.5 cm.


Answered by Expert 7th March 2015, 1:38 PM
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