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Construct a triangle similar to given triangle ABC in which AB=6cm, BC=5cm and B=60o, with its sides equal to of the corresponding sides of ABC

OR

Draw a ABC with side BC = 6 cm, AB = 5 cm and ABC = 60o. Construct a A'BC' similar to ABC such that sides of A'BC' are of the corresponding sides of ABC.

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

Steps of construction:

(i) Draw a ABC with side AB = 6 cm, BC = 5 cm and ABC = 60o.

(ii) Draw a ray AX making an acute angle with AB on the opposite side of vertex C.

(iii) Locate 7 points, A1, A2, A3, A4 A5, A6, A7 (as 7 is greater between 5and 7), on line AX such that AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6 = A6A7.

(iv) Join BA5 and draw a line through A7 parallel to BA5 to intersect extended line segment AB at point B'.

(v) Draw a line through B' parallel to BC intersecting the extended line segment AC at C'. AB'C' is the required triangle.

OR

Steps of construction:

(i) Draw a ABC with side BC = 6 cm, AB = 5 cm and ABC = 60o.

(ii) Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

(iii) Locate 4 points (as 4 is greater in 3 and 4), B1, B2, B3, B4, on line segment BX such that BB1 = B1B2 = B2B3 = B3B4.

(iv) Join B4C and draw a line through B3, parallel to B4C intersecting BC at C'.

(iv) Draw a line through C' parallel to AC intersecting AB at A'. A'BC' is the required triangle.

Answered by Expert 4th June 2014, 3:23 PM
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