CBSE Class 9 Answered
Construct a triangle PQR with base PQ = 8.4
cm, P
= 45o and PR - QR = 2.8 cm.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Steps of Construction :
1. Draw the base PQ = 8.4 cm and at point P make an angle of 45o.
2. Cut the line segment PS equal to the length of PR - QR, that is 2.8 cm
3. Join SQ and draw the perpendicular bisector, say
AB of SQ.
4. Let it intersect BX at a point R. Join RQ
Then, PQR is the required triangle.
Answered by | 04 Jun, 2014, 03:23: PM
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