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CBSE Class 9 Answered

Construct a triangle ABC in which B = 60o, C = 45o and the perimeter of the triangle is 11 cm.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

Steps of Construction :

1. Draw a line segment PQ = 11 cm (= AB + BC + CA).

2. At P construct an angle of 60° and at Q, an angle of 45°.

3. Bisect these angles. Let the bisectors of these angles intersect at a point A.

4. Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.

5. Join AB and AC

ABC is the required triangle.

Answered by | 04 Jun, 2014, 03:23: PM

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