ICSE Class 10 Answered
Construct a rhombus ABCD of side 4.8 cm and ∠BCD = 135°, by using a ruler and compasses only. Indicate the point of symmetry with the letter O.
Asked by Topperlearning User | 27 May, 2016, 12:15: PM
Expert Answer
Steps of Construction:
i) Draw a line segment BC = 4.8 cm
ii) With centre C and a convenient radius draw an arc to cut BC at E.
iii) Taking E, as the centre and the same radius draw an arc intersecting the previous arc at F.
iv) Mark G and H in the same manner.
v) Taking F and G as the centres draw arcs intersecting each other at I.
vi) Taking I and H as the centres draw arcs intersecting each other at j.
vii) Join CJ and extend further so that CD = 4.8 cm.
viii) Construct AB parallel to DC and AD parallel to BC.
ix) Join BD and AC which intersects each other at O.
x) O is the required point of symmetry and ABCD is the required rhombus
Answered by | 27 May, 2016, 02:15: PM