CBSE Class 9 Answered
Construct a ABC such that B = 60o, C = 45o and its perimeter is 10 cm.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Steps of Construction :
1. Draw a line segment, say XY equal to BC + CA + AB = 10 cm.
2. Make angle LXY equal to 60o and angle MYX equal to 45o.
3. Bisect LXY and MYX. Let these bisectors intersect at point A.
4. Draw perpendicular bisector PQ of AX and RS of AY.
5. Let PQ intersect XY at B and RS intersect XY at C.
6. Join AB and AC.
ABC is the required triangle.
Answered by | 04 Jun, 2014, 03:23: PM
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