Consider the electrophilic addition ofone equivalent HBr to 1-methylcyclopentadiene.Under the reaction conditions,all possible allylic carbocations form.which of the following is kinetically favoured product and which is thermodynamically favored product.explain
Asked by sandossh
22nd March 2018,
2:09 PM
Answered by Expert
Answer:
The rate-determining step for the product is the stability of carbocation. The order of stability for carbocation is:
Tertiary> Benzyl cation = allyl cation > secondary cation > primary cation > methyl cation > vinyl cation
Hence the thermodynamically stable product will be compound D which formed by most stable 3ocation.
And the rest are kinetically stable products formed by the allylic carbocation.
Answered by Expert
22nd March 2018,
3:30 PM
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