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CBSE Class 10 Answered

Chapter 9 (Some applications of trigometri) Example 6 , how it solved PD+8 = PDroot3 then it directly got PD=8/root3-1 how ?
Asked by edayoor | 16 Feb, 2019, 12:20: PM
answered-by-expert Expert Answer
begin mathsize 12px style angle end styleBPD = 90 - begin mathsize 12px style angle end styleQPB = 90-30 = 60°
Hence tan 60 = BD/PD   or   √3 =  BD/PD  or BD = √3 PD ..................(1)
 
begin mathsize 12px style angle end styleAPB = 45
hence tan 45 = AC/PC   or  1 = AC/PC  or  AC = PC or BD = PD+DC = PD+8  .........................(2)
 
[ In eqn.(2) we used BD = AC and DC=AB=8 ]
 
from (1) and (2),  √3 PD = PD+8   or  PD(√3 - 1) = 8   or PD = 8/ (√3 - 1) = 4(√3 + 1)m
Answered by Thiyagarajan K | 16 Feb, 2019, 01:30: PM

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