# Remainder Theorem Free Doubts and Solutions

### CBSE - IX - Mathematics - Polynomials

## if 2x^3+ax^2+3x-5 is divided by x-2 the remainder is 5 then find a

**niharikapant2002**5th June 2018, 1:49 PM

### CBSE - IX - Mathematics - Polynomials

## What is the remainder when h(y) = 4y3 - 12y2 + 14y - 3 is divided by (2x - 1)

**Topperlearning User**18th September 2017, 10:06 AM

### CBSE - IX - Mathematics - Polynomials

## Check whether (i) The polynomial 2x4 - 5x3 - 2x + 5 is a multiple of x - 1.(ii) 7x2 - 7x + 2x3 - 30 is a multiple of 2x + 5.

**Topperlearning User**18th September 2017, 9:46 AM

### CBSE - IX - Mathematics - Polynomials

## Using Remainder Theorem, prove that p(x) = 6x3 + 19x2 + 21x + 9 is completely divisible by 2x + 3.

**Topperlearning User**18th September 2017, 9:42 AM

### CBSE - IX - Mathematics - Polynomials

## Check whether (x - 1) is a multiple of x3 - 3x2 + 3x - 4.

**Topperlearning User**18th September 2017, 9:42 AM

### CBSE - IX - Mathematics - Polynomials

## Prove that x + 3 is a multiple of q(x) = x3 + 6x2 + 11x + 6 using Remainder theorem.

**Topperlearning User**18th September 2017, 9:35 AM

### CBSE - IX - Mathematics - Polynomials

## If the polynomial ax3 + 3x2 - 13 and 2x3 - 5x + a, when divided by (x + 2) leaves the same remainder, find the value of 'a'.

**Topperlearning User**18th September 2017, 9:32 AM

### CBSE - IX - Mathematics - Polynomials

## If the polynomial p(x) = x3 - 3x2 + ax - b is such that when divided by (x - 2 ) and (x + 2), the remainders are 21 and 1 respectively. Find the values of a and b.

**Topperlearning User**18th September 2017, 9:31 AM

### CBSE - IX - Mathematics - Polynomials

## Find remainder using Remainder theorem:(i) r(t) = t3 + 6t2 + 2t - 2 is divided by (3t + 1)(ii) g(y) = y3 - 6y2 + 2y - 4 is divided by (1 - 3y)

**Topperlearning User**18th September 2017, 9:30 AM

### CBSE - IX - Mathematics - Polynomials

## Using Remainder Theorem, obtain the remainder when(i) p(x) = 2x4 - 3x3 + x2 - x + 5 is divided by (x - 2)(ii) q(x) = 4x3 - 12x2 + 14x - 3 is divided by (2x - 1)

**Topperlearning User**18th September 2017, 9:25 AM

### CBSE - IX - Mathematics - Polynomials

## The polynomials p(x) = ax3 + 3x2 - 3 and q(x) = 2x3 - 5 + a , when divided by (x - 4) leave the remainders R1 and R2. Find 'a' if R1 + R2 = 0.

**Topperlearning User**18th September 2017, 9:20 AM

### CBSE - IX - Mathematics - Polynomials

## WHAT IS THE REMAINDER WHEN 5Xcube-7Xsquare+3X+13 IS DIVIDED BE X/2+1

**Keerthi**8th June 2017, 8:20 PM

### CBSE - IX - Mathematics - Polynomials

## <div>DIVIDE <img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=4f0c6a28d5d9b80d5278c5c49c1a5e35.png" alt="X to the power of 4 minus 3 X squared plus 2 X plus 5 space space space B Y space space X minus 1 space space F I N D space Q U O T I E N T space A N D space T H E space R E M A I N D E R space " align="middle" /></div>

**Sunny**24th May 2017, 7:50 PM

### CBSE - IX - Mathematics - Polynomials

## x + 6 is a factor of the polynomial mx3 + 13x2 - 69x - 18. The polynomials 3x2 - ax + 6m and x 3 + ax2 - 2 leave the same remainder when divided by (x - 2). Find the values of a and m. how to solve these type of questions

**rajivjoshigoldtech**9th September 2016, 12:12 PM

### CBSE - IX - Mathematics - Polynomials

## The polynomials x3+2x2-5ax-8 and x3+ax2-12x-6 when divided by (x-2) and (x-3) leave remainders p and q respectively.If q-p=10;what is the value of ? Sir all these numbers immediately after x are powers of x.

**Harshit Saini**10th July 2015, 9:06 PM

### CBSE - IX - Mathematics - Polynomials

##
###
Factorise:
(i) x^{3} - 2x^{2} - x + 2 (ii) x^{3} - 3x^{2} - 9x - 5
(iii) x^{3} + 13x^{2 }+ 32x + 20 (iv) 2y^{3} + y^{2} - 2y - 1

###
Factorise:
(i) x^{3} - 2x^{2} - x + 2 (ii) x^{3} - 3x^{2} - 9x - 5
(iii) x^{3} + 13x^{2 }+ 32x + 20 (iv) 2y^{3} + y^{2} - 2y - 1

^{3}- 2x

^{2}- x + 2 (ii) x

^{3}- 3x

^{2}- 9x - 5

^{3}+ 13x

^{2 }+ 32x + 20 (iv) 2y

^{3}+ y

^{2}- 2y - 1

**Turjo Bhattacharjee**14th June 2015, 9:23 PM

### CBSE - IX - Mathematics - Polynomials

## <div><img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=908030d729a10110e896bbf1e786348d.png" alt="x cubed minus 6 x squared plus 2 x minus 4 space d i v i d e d space b y space 3 x minus 1" align="middle" /></div>

**KALAPANA.KOTAK**16th July 2014, 8:41 AM

### CBSE - IX - Mathematics - Polynomials

## <div>If p(x) = <img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=0e6247fd34f4bd68a49257bf3a69dd38.png" alt="4 x cubed space minus space 12 x squared plus space 14 x space minus space 3" align="middle" />. Find remainder when p(x) is divided by 2x-1. Also verify the result by actual division.</div>

**vatsalchoudhary41**29th June 2014, 11:27 AM

### CBSE - IX - Mathematics - Polynomials

## What must be added to *x^4+6x^3+19x^2+30x* to make it a perfect square?

**to make it a perfect square?**

*x^4+6x^3+19x^2+30x***ddastez**4th June 2014, 9:00 PM

### CBSE - IX - Mathematics - Polynomials

## If f(x) = x4 - 2x3 + 3x2 - ax + b is divided by(x - 1) and (x + 1), it leaves the remainder 5 and 19 respectively. Find 'a' and 'b'.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Polynomials

## The polynomials kx3 + 3x2 - 8 and 3x3 - 5x + k are divided by x + 2. If the remainder in each case is the same, find the value of k.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Polynomials

## Find the remainder when 3x3 - 4x2 + 7x - 5 is divided by (x - 3) and (x + 3).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Polynomials

## If p(x) = x3 - ax2 + bx + 3 leaves a remainder - 19 when divided by (x + 2) and a remainder 17 when divided by (x - 2), prove that a + b = 6.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Polynomials

## Find the reminder when 3x3 - 4x2 + 7x - 5 is divided by (x - 3) and (x + 3).

**Topperlearning User**4th June 2014, 1:23 PM