# Area Of Triangles Free Doubts and Solutions

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## A piece of paper is in the shape of a right-angled triangle and is cut along a line that is parallel to the hypotenuse, leaving a smaller triangle. There was 35% reduction in the length of the hypotenuse of the triangle. If the area of the original triangle was 34 square inches before the cut, what is the area (in square inches) of the smaller triangle?

**rushabhjain.av**1st April 2019, 7:56 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Prove that a median divides a triangle into two triangle of equal area

**bhardwajvishesh2004**28th November 2018, 4:18 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## find area of a triangle whose sideas are 13cm,14cm and 15cm

**prashantyadav231314**31st October 2018, 3:57 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## only 1st n 3rd are in doubt

**Bhushan**12th October 2018, 4:51 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonals AC and BD of quad. ABCD intersect each other at P. Show that: ar( CPD) = ar(APD) x ar(BPC)

**Vikas**27th February 2018, 11:16 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## the sides of atriangular plt are in the ratio of 3:5:7 and the perimeter is 300 m .find its area

**abhik80365**25th February 2018, 8:18 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## If the medians of a triangle ABC intersect at G,prove that area of triangle BCG=1/3 area of triangle ABC

**laxmi.agarwal055**21st February 2018, 7:04 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonal AC and BD of quad. ABCD intersect at P. Show that ar ( APB ) X ar ( CPD) = ar ( APD) X ar ( BPC ) ( PLS EXPERTS ANS URGENTLY)

**nisha_vini29**17th January 2018, 11:55 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a //gm whose diagonals intersect at O. P is a point on BQ , then prove that : (i) ar ( ADO) = ar ( DOC ) and ar ( ABP ) = ar ( BCP ) ( PLS ANS URGENTLY )

**nisha_vini29**17th January 2018, 11:40 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## find the area of largest triangle that can be inscribed in a semi circle of radius r

**sonalibansal168**16th January 2018, 7:43 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## how does a median divide a triangle in two congruent triangles? can you explain with an example, elaborated.

**ishita605**2nd January 2018, 8:36 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## My maths SA1 exam is on 12th of oct, how should i study?

**Jitendra**28th September 2017, 11:37 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## clarify question 6 in very easy method

**md775016**20th August 2017, 7:10 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## 2 buildings of heights 26 m and 14 m are exactly on opposite sides of the road.If the distance between their tops is 15 m, find the width of the road ?

**Vikas**13th July 2017, 10:48 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

##
ABCD is a parallelogram. E and F are points on side AB such that AE = EF = FB.

Show that ar (DAE) = 1/6 ar (ABCD).

ABCD is a parallelogram. E and F are points on side AB such that AE = EF = FB.

Show that ar (DAE) = 1/6 ar (ABCD).

**gpnkumar0**7th March 2017, 6:59 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## in a parallelogram ABCD, AB=12cm amd AD=8cm. the bisector of <A meets DC at P. AP and BC are produced to meet at Q as shown in the figure. find the lenght of CQ

**sanjeev.mami**10th March 2016, 10:37 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## IN NCERT BOOK OF MATHS,
PG NO.-163
QUE.6
IT IS REQUIRED TO PROVE THE AREA OF TRIANGLES EQUAL SO COULDN'T WE DO IT SIMPLY MAKING BOTH TRIANGLES CONGRUENT BY(S.S.S RULE).WHY IS THERE A NEED TO DO IT BY AAS AND DRAWING ALTITUDE?

**Harshita Singh**10th March 2016, 9:06 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## P and Q are the mid points of sides AB and BC of a triangle ABC and R is the mid point of AP, show that. 1. AR(PQR) = 1/2 AR(ARC) 2. AR(RQC) = 3/8 AR(ABC) 3. AR(PBQ) = AR(ARC)

**dimplesharma0810**28th February 2016, 8:53 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## answer the following:
1. Triangle PQR is an equilateral triangle with PM perpendicular to QR. prove that the area of triangle PQM=area of triangle PRM.
2. a solid right circular cone of radius 4cm and height 7cm is melted to form a sphere. find the radius of the sphere.

**skbl2009**18th January 2016, 10:39 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABC is an acute angled triangle and CD be the altitude through C. If AB = 6 cm and CD = 8 cm, then find the distance between mid-points of AD and BC.

**a.behera67**2nd January 2016, 9:19 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## prove that the area of an equilateral triangle is equal to * where a is the side of the traingle

**Aniket**5th December 2015, 12:45 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In a parallelogram ABCD, if its area is 20 cm2, find the area of the ABC and the distance between the sides AB and CD, if AB = 5 cm.

**Topperlearning User**26th October 2015, 8:44 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Y r the new book not present in this site

**Rahul**7th September 2015, 10:51 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## state mid point theoram

**rrdave2611**20th March 2015, 9:10 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a square. M is a point on AB such that AM=MB. P&Q are points on sides AD & extended CB such that CM is perpendicular to PQ. Show that ar(CPM)=(CQM)

**archita123**13th March 2015, 4:42 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

##
In triangle PQR, base QR is divided at X such that QX=1/2 XR.Prove that ar (PQX) =1/3 ar (PQR).

In triangle PQR, base QR is divided at X such that QX=1/2 XR.Prove that ar (PQX) =1/3 ar (PQR).

**rkjha_in**9th March 2015, 5:00 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

- ABCD is a trapezium with parallel sides AB=a and DC=b. If E and F are midpoints of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFE and EFCD is??

- ABCD is a trapezium with parallel sides AB=a and DC=b. If E and F are midpoints of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFE and EFCD is??

**kumar.ashlesha**12th December 2014, 8:45 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## If AD is a median of triangle ABC and P is a point on AC such that ar(ADP): ar(ABD) = 2:3, then ar(PDC) : ar (ABC) is??

**kumar.ashlesha**12th December 2014, 8:37 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## you have given rd sharma solutions for 9th maths. but where i can see its questions . i donot have rd sarma book

**narayan.cholkar**17th September 2014, 8:09 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Show that the median of a triangle divides it into two triangles of equal areas.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the given figure, ABCD is a quadrilateral. A line through D parallel to AC meets BC produced at E. Prove that ar(ABE) = ar quad. ABCD)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the given fig., M, N are points on sides PQ and PR respectively of PQR such that ar(QRN) = ar(QRM). Show that MN||QR.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## If medians of a triangle ABC intersects at G show that ar (AGB) = ar (AGC) = ar(BGC) = ar (ABC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## PQRS is a trapezium with PQ||SR. A line parallel to PR intersects PQ at L and QR at M. Prove that ar(PSL) = ar (PRM)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## The median BE and CF of ABC intersects at G. Prove that ar(GBC) = ar(quad AFGE)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## A point E is taken as the midpoint of the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that ar (ADF) = ar(ABFC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## A point D is taken on the base BC of a ABC and AD is produced to E, such that DE = AD. Show that ar (BCE) = ar(ABC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the figure, ABCD is a trapezium in which AB||DC. Prove that ar(AOD) = ar(BOC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the figure, PQ||DC||AB. Prove that ar(ACP) = ar(BDQ)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABC and ABD are on the same base AB. If line segment CD is bisected by AB at O, show that ar (ABC) = ar(ABD)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In figure, E is any point on median AD of a ABC. Show that ar (ABE) = ar (ACE).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that area ABCD = area PBQR.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCDE is pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) Area ACB = Area ACF (ii) area AEDF = area ABCDE

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonal AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## XY is a line parallel to the side BC of a ABC. BE AC and CF AB meets XY at E and F respectively. Show that ar (ABE) = ar (ACF).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the figure AP BQ CR. Prove that ar (AQC) = ar (PBR).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## A point D is taken on the side BC of a ABC such that BD = 2DC. Prove that ar (ABD) = 2 ar (ADC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Show that the median of a triangle divides it into two triangles of equal area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonals AC and BD of a trapezium ABCD with AB DC intersect each other at O. Prove that: ar (AOD) = ar (BOC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCDE is a pentagon. A line through B is parallel to AC meets DC produced at F. Show that ar (ABC) = ar (ACF).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Prove that the diagonal of a parallelogram divides it into two triangles of equal area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## G is the centroid of the ABC, such that GD = 3 cm and BC = 4 cm. Find the area of the ABC.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Prove that the triangles between the same parallels and on the same base are equal in area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. show that

**shweta mondal**12th January 2014, 9:39 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**13th December 2013, 10:29 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In triangle ABC, D is the mid point of AB. P is any point on BC. CQ PD meets AB at Q. Show that ar (BPQ) = ar (ABC).

**Topperlearning User**13th December 2013, 1:36 AM