# Area Of Triangles Free Doubts and Solutions

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonals AC and BD of quad. ABCD intersect each other at P. Show that: ar( CPD) = ar(APD) x ar(BPC)

**Vikas**27th February 2018, 11:16 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## the sides of atriangular plt are in the ratio of 3:5:7 and the perimeter is 300 m .find its area

**abhik80365**25th February 2018, 8:18 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## If the medians of a triangle ABC intersect at G,prove that area of triangle BCG=1/3 area of triangle ABC

**laxmi.agarwal055**21st February 2018, 7:04 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonal AC and BD of quad. ABCD intersect at P. Show that ar ( APB ) X ar ( CPD) = ar ( APD) X ar ( BPC ) ( PLS EXPERTS ANS URGENTLY)

**nisha_vini29**17th January 2018, 11:55 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a //gm whose diagonals intersect at O. P is a point on BQ , then prove that : (i) ar ( ADO) = ar ( DOC ) and ar ( ABP ) = ar ( BCP ) ( PLS ANS URGENTLY )

**nisha_vini29**17th January 2018, 11:40 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## find the area of largest triangle that can be inscribed in a semi circle of radius r

**sonalibansal168**16th January 2018, 7:43 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## how does a median divide a triangle in two congruent triangles? can you explain with an example, elaborated.

**ishita605**2nd January 2018, 8:36 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## My maths SA1 exam is on 12th of oct, how should i study?

**Jitendra**28th September 2017, 11:37 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## clarify question 6 in very easy method

**md775016**20th August 2017, 7:10 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## 2 buildings of heights 26 m and 14 m are exactly on opposite sides of the road.If the distance between their tops is 15 m, find the width of the road ?

**Vikas**13th July 2017, 10:48 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

##
ABCD is a parallelogram. E and F are points on side AB such that AE = EF = FB.

Show that ar (DAE) = 1/6 ar (ABCD).

ABCD is a parallelogram. E and F are points on side AB such that AE = EF = FB.

Show that ar (DAE) = 1/6 ar (ABCD).

**gpnkumar0**7th March 2017, 6:59 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## in a parallelogram ABCD, AB=12cm amd AD=8cm. the bisector of <A meets DC at P. AP and BC are produced to meet at Q as shown in the figure. find the lenght of CQ

**sanjeev.mami**10th March 2016, 10:37 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## IN NCERT BOOK OF MATHS,
PG NO.-163
QUE.6
IT IS REQUIRED TO PROVE THE AREA OF TRIANGLES EQUAL SO COULDN'T WE DO IT SIMPLY MAKING BOTH TRIANGLES CONGRUENT BY(S.S.S RULE).WHY IS THERE A NEED TO DO IT BY AAS AND DRAWING ALTITUDE?

**Harshita Singh**10th March 2016, 9:06 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## P and Q are the mid points of sides AB and BC of a triangle ABC and R is the mid point of AP, show that. 1. AR(PQR) = 1/2 AR(ARC) 2. AR(RQC) = 3/8 AR(ABC) 3. AR(PBQ) = AR(ARC)

**dimplesharma0810**28th February 2016, 8:53 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## answer the following:
1. Triangle PQR is an equilateral triangle with PM perpendicular to QR. prove that the area of triangle PQM=area of triangle PRM.
2. a solid right circular cone of radius 4cm and height 7cm is melted to form a sphere. find the radius of the sphere.

**skbl2009**18th January 2016, 10:39 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABC is an acute angled triangle and CD be the altitude through C. If AB = 6 cm and CD = 8 cm, then find the distance between mid-points of AD and BC.

**a.behera67**2nd January 2016, 9:19 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## <div>prove that the area of an equilateral triangle is equal to <img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=16f881580a6c79a452fcd826c88f813a.png" alt="square root of 3 divided by 4" align="middle" />*<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=f8178eb443730c56b0cf6a6c2539e370.png" alt="a squared" align="middle" /> where a is the side of the traingle</div> <div> </div>

**Aniket**5th December 2015, 12:45 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In a parallelogram ABCD, if its area is 20 cm2, find the area of the ABC and the distance between the sides AB and CD, if AB = 5 cm.

**Topperlearning User**26th October 2015, 8:44 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Y r the new book not present in this site

**Rahul**7th September 2015, 10:51 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## state mid point theoram

**rrdave2611**20th March 2015, 9:10 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a square. M is a point on AB such that AM=MB. P&Q are points on sides AD & extended CB such that CM is perpendicular to PQ. Show that ar(CPM)=(CQM)

**archita123**13th March 2015, 4:42 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

##
In triangle PQR, base QR is divided at X such that QX=1/2 XR.Prove that ar (PQX) =1/3 ar (PQR).

In triangle PQR, base QR is divided at X such that QX=1/2 XR.Prove that ar (PQX) =1/3 ar (PQR).

**rkjha_in**9th March 2015, 5:00 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

- ABCD is a trapezium with parallel sides AB=a and DC=b. If E and F are midpoints of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFE and EFCD is??

- ABCD is a trapezium with parallel sides AB=a and DC=b. If E and F are midpoints of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFE and EFCD is??

**kumar.ashlesha**12th December 2014, 8:45 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## If AD is a median of triangle ABC and P is a point on AC such that ar(ADP): ar(ABD) = 2:3, then ar(PDC) : ar (ABC) is??

**kumar.ashlesha**12th December 2014, 8:37 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## you have given rd sharma solutions for 9th maths. but where i can see its questions . i donot have rd sarma book

**narayan.cholkar**17th September 2014, 8:09 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Show that the median of a triangle divides it into two triangles of equal areas.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the given figure, ABCD is a quadrilateral. A line through D parallel to AC meets BC produced at E. Prove that ar(ABE) = ar quad. ABCD)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the given fig., M, N are points on sides PQ and PR respectively of PQR such that ar(QRN) = ar(QRM). Show that MN||QR.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## If medians of a triangle ABC intersects at G show that ar (AGB) = ar (AGC) = ar(BGC) = ar (ABC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## PQRS is a trapezium with PQ||SR. A line parallel to PR intersects PQ at L and QR at M. Prove that ar(PSL) = ar (PRM)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## The median BE and CF of ABC intersects at G. Prove that ar(GBC) = ar(quad AFGE)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## A point E is taken as the midpoint of the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that ar (ADF) = ar(ABFC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## A point D is taken on the base BC of a ABC and AD is produced to E, such that DE = AD. Show that ar (BCE) = ar(ABC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the figure, ABCD is a trapezium in which AB||DC. Prove that ar(AOD) = ar(BOC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the figure, PQ||DC||AB. Prove that ar(ACP) = ar(BDQ)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABC and ABD are on the same base AB. If line segment CD is bisected by AB at O, show that ar (ABC) = ar(ABD)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In figure, E is any point on median AD of a ABC. Show that ar (ABE) = ar (ACE).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that area ABCD = area PBQR.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCDE is pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) Area ACB = Area ACF (ii) area AEDF = area ABCDE

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonal AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## XY is a line parallel to the side BC of a ABC. BE AC and CF AB meets XY at E and F respectively. Show that ar (ABE) = ar (ACF).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the figure AP BQ CR. Prove that ar (AQC) = ar (PBR).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## A point D is taken on the side BC of a ABC such that BD = 2DC. Prove that ar (ABD) = 2 ar (ADC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Show that the median of a triangle divides it into two triangles of equal area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonals AC and BD of a trapezium ABCD with AB DC intersect each other at O. Prove that: ar (AOD) = ar (BOC).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCDE is a pentagon. A line through B is parallel to AC meets DC produced at F. Show that ar (ABC) = ar (ACF).

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Prove that the diagonal of a parallelogram divides it into two triangles of equal area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## G is the centroid of the ABC, such that GD = 3 cm and BC = 4 cm. Find the area of the ABC.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Prove that the triangles between the same parallels and on the same base are equal in area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. show that

**shweta mondal**12th January 2014, 9:39 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**13th December 2013, 10:29 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In triangle ABC, D is the mid point of AB. P is any point on BC. CQ PD meets AB at Q. Show that ar (BPQ) = ar (ABC).

**Topperlearning User**13th December 2013, 1:36 AM