# Area Of Parallelograms Free Doubts and Solutions

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD and PQRC are 2 rectangles. Q is a midpoint of AC, P is a midpoint of DC and R is a mid point of BC. FIND ratio of area( ABCD )and area ( PQRC ) ? ( pls experts ans urgently )

**Vikas**18th January 2018, 12:31 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a //gm and ar ( BCP ) = ar ( DPQ ) . Prove that ar ( BPC ) = ar ( DPQ) , provided BC = CQ ( P[LS EXPERTS ANS URGENTLY )

**Vikas**18th January 2018, 12:19 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In Parallelogram ABCD o is any point on the diagonal bd .prove that area of triangle OAB=area of triangle COB

**Muruga**17th January 2018, 4:43 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## AD is one of the diagonal of quad. ABCD . AM and CN are perpendiculars from A and C respectively on BD. Show that ar ( quad. ABCD ) = 1/2 BD X ( CN + AM )

**Vikas**16th January 2018, 11:58 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Show that area of rhombus is half the product of its diagonals .

**Vikas**16th January 2018, 11:50 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a trapezium In which AB DC and DC = 40 cm and AB = 60 cm. If X and Y are respectively, the mid points of AD and BC, prove that ar (DCYX) = ar (XYBA).

**Topperlearning User**17th August 2017, 2:01 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## The figure shows two parallelograms ABCD and ABEF. Prove that Area of ADF = area of BCE.

**Topperlearning User**17th August 2017, 1:59 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium.

**Topperlearning User**17th August 2017, 1:58 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In a quadrilateral ABCD, M is the mid point of AC. Prove that ar (ABMD) = ar (DMBC).

**Topperlearning User**17th August 2017, 1:57 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a parallelogram of area 900 sq. cm. AP is drawn perpendicular to BC and AQ is perpendicular to DC. If AP = 24 cm and AQ = 18.75 cm. Calculate (i) AB (ii) BC (iii) area of ABC.

**Topperlearning User**17th August 2017, 1:56 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## If the diagonals AC, BD of a quadrilateral ABCD, intersect at O, and divide it into four triangles of equal area, Show that the quadrilateral is a parallelogram.

**Topperlearning User**17th August 2017, 1:54 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a trapezium in which, AB DC and DC = 40 cm and AB = 60 cm. If X and Y are, respectively, the mid points of AD and BC, prove that XY = 50 cm.

**Topperlearning User**17th August 2017, 1:54 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## The diagonals of a parallelogram ABCD intersect at point O. Through O, a line is drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area that is ar (APQB) = ar (PQCD).

**Topperlearning User**17th August 2017, 1:53 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## PQRS and ABRS are two parallelograms as shown and Y is any point on BR. If area (AYS)= 56 sq cm, then what is the area of parallelogram PQRS?

**Topperlearning User**17th August 2017, 1:53 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD and BCFE are parallelograms. If area of triangle EBC = 480 sq. cm. Calculate (i) area of parallelogram ABCD (ii) area of parallelogram BCFE.

**Topperlearning User**17th August 2017, 1:50 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Find the area of the parallelogram whose adjacent sides are 12cm and 17 cm.Also find the altitude provided that diagonal is 25 cm ?

**Vikas**21st May 2017, 11:47 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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**Devraj**17th April 2017, 4:30 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In ram`s field prove that each angle is 90 degree

**Suraj**27th March 2017, 12:44 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## PSDA is a parllelogram in which PQ = QR = RS and AP parellel to BQ parellel to CR. prove that area ( tiangle PQE = area tri CFD.

**kksharma45636**15th March 2016, 10:42 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a trapezium with parallel sides AB=a cm and DC=b cm .E and F are midpoint of the non parallel sides.find the ratio of area [ABFE] and area [EFCD].
SOLVE IT.
ALSO,explain how EF= a+b/2.

**ranjitrk1**14th March 2016, 10:16 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Parallelogram ABCD and rectangle ABEF are on the same base and have equal areas. Show that perimeter of the parallelogram is greater than that of rectangle.

**dimplesharma0810**28th February 2016, 8:57 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## sir
can you tell me wat are the key points in chapters qudrilateral, ares of parallelogram and triangle ,circles and in surface areas and volumes

**seeni2005**6th February 2016, 5:35 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

- in quad. ABCD . P is the mid pt .of AC . P.T. the ar(ABCD)=ar(BCPD)
- ABCD is a parellelogram ,O is a on the side AC. ar(AOB)=ar(AOD).
- In cyclic quad.angB-angD 60 deg. ,show that :smaller of those is also 60 d4eg.

**aninadathoorsridharan**25th January 2016, 7:08 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## two paralleograms are on equal bases and between same paralles. the ratio of their areas is 1:1. prove it

**rrdave2611**20th March 2015, 9:04 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a parallelogram. E is a point on BA such that BE=2FA and F is a point on DC such that DF=2FC. prove that AECF is a parallelogram whose area is one third of the area of parallelogram ABCD.

**manavmansvi**7th March 2015, 11:38 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## the side AB of a parallelogram ABCD is produced to any point P. a line through A and parallel to CP meets CB produced at Q and then parellelogram PBQR is completed. show that area ABCD= area PBQR.

**manavmansvi**7th March 2015, 11:25 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the given figure, M is a point in the interior of a parallelogram PQRS. Show that (i) ar(PMQ) + ar(MRS) = (||gm PQRS) (ii) ar(PMS) + ar(MQR) = ar(PMQ) + ar(MRS)

**Topperlearning User**13th August 2014, 2:57 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Prove that the parallelograms on the same base and between same parallels are equal in area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## ABCD is a parallelogram in which CD = 15 cm, its corresponding altitude AM is 8 cm and CN AD. If CN = 10 cm, then find the length of AD.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## In the given figure, ABCD is parallelogram and AE DC. If AB is 20 cm and the area of parallelogram ABCD is 80 cm2, find AE.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that: ar(APB) = ar(BQC)

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## PQRS and ABRS are parallelograms and X is any point on side BR. Show that: (i) area PQRS = area ABRS (ii) area AXS = area PQRS

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## Prove that parallelograms on the same base and between the same parallels are equal in area.

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

## P is a point in the interior of a parallelogram ABCD. Show that (i) Area APB + Area PCD = area ABCD (ii) Area APD + Area PBC = area APB + area PCD

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**4th June 2014, 1:23 PM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**13th December 2013, 8:00 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**13th December 2013, 7:42 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**12th December 2013, 10:31 AM

### CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

**Topperlearning User**12th December 2013, 12:45 AM