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Area Of Parallelograms Free Doubts and Solutions

CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

Please solve this question 

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Asked by vikasg13.hardware 23rd June 2018, 5:32 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD and PQRC are 2 rectangles. Q  is a midpoint of AC, P is a midpoint of DC and R is a mid  point  of BC. FIND  ratio  of area( ABCD )and  area ( PQRC ) ? ( pls experts ans urgently )

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Asked by Vikas 18th January 2018, 12:31 AM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD is a //gm and ar ( BCP )  = ar ( DPQ )  . Prove that ar ( BPC ) = ar ( DPQ) , provided BC = CQ  ( P[LS EXPERTS ANS URGENTLY )

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Asked by Vikas 18th January 2018, 12:19 AM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

In Parallelogram ABCD o is any point on the diagonal bd .prove that area of triangle OAB=area of triangle COB

Asked by Muruga 17th January 2018, 4:43 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

AD is one of the diagonal of  quad. ABCD . AM and CN are  perpendiculars from A and C respectively on BD. Show that ar ( quad. ABCD ) = 1/2  BD X ( CN + AM )

Asked by Vikas 16th January 2018, 11:58 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

Show that area of rhombus is half the product of its diagonals .

Asked by Vikas 16th January 2018, 11:50 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD is a trapezium In which AB  DC and DC = 40 cm and AB = 60 cm. If X and Y are respectively, the mid points of AD and BC, prove that ar (DCYX) = ar (XYBA).

Asked by Topperlearning User 17th August 2017, 2:01 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

The figure shows two parallelograms ABCD and ABEF. Prove that Area of ADF = area of BCE.

Asked by Topperlearning User 17th August 2017, 1:59 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium.

Asked by Topperlearning User 17th August 2017, 1:58 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

In a quadrilateral ABCD, M is the mid point of AC. Prove that ar (ABMD) = ar (DMBC).

Asked by Topperlearning User 17th August 2017, 1:57 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD is a parallelogram of area 900 sq. cm. AP is drawn perpendicular to BC and AQ is perpendicular to DC. If AP = 24 cm and AQ = 18.75 cm. Calculate (i) AB (ii) BC (iii) area of ABC.

Asked by Topperlearning User 17th August 2017, 1:56 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

If the diagonals AC, BD of a quadrilateral ABCD, intersect at O, and divide it into four triangles of equal area, Show that the quadrilateral is a parallelogram.

Asked by Topperlearning User 17th August 2017, 1:54 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD is a trapezium in which, AB  DC and DC = 40 cm and AB = 60 cm. If X and Y are, respectively, the mid points of AD and BC, prove that XY = 50 cm.

Asked by Topperlearning User 17th August 2017, 1:54 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

The diagonals of a parallelogram ABCD intersect at point O. Through O, a line is drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area that is ar (APQB) = ar (PQCD).

Asked by Topperlearning User 17th August 2017, 1:53 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

PQRS and ABRS are two parallelograms as shown and Y is any point on BR. If area (AYS)= 56 sq cm, then what is the area of parallelogram  PQRS?

Asked by Topperlearning User 17th August 2017, 1:53 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD and BCFE are parallelograms. If area of triangle EBC = 480 sq. cm. Calculate (i) area of parallelogram ABCD                   (ii) area of parallelogram BCFE.

Asked by Topperlearning User 17th August 2017, 1:50 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

Find the area of the parallelogram whose adjacent sides are 12cm and 17 cm.Also find the altitude provided that diagonal is 25 cm ?

Asked by Vikas 21st May 2017, 11:47 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

In ram`s field prove that each angle is 90 degree

Asked by Suraj 27th March 2017, 12:44 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

PSDA is a parllelogram in which PQ = QR = RS and AP  parellel to BQ parellel to CR. prove that area ( tiangle PQE = area tri CFD.

Asked by kksharma45636 15th March 2016, 10:42 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD is a trapezium with parallel sides AB=a cm and DC=b cm .E and F are midpoint of the non parallel sides.find the ratio  of area [ABFE] and area [EFCD].
SOLVE IT.
ALSO,explain how EF= a+b/2.

Asked by ranjitrk1 14th March 2016, 10:16 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

Parallelogram ABCD and rectangle ABEF are on the same base and have equal areas. Show that perimeter of the parallelogram is greater than that of rectangle.

Asked by dimplesharma0810 28th February 2016, 8:57 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

sir 
      can you tell me wat are the key points in chapters qudrilateral, ares of parallelogram and triangle ,circles and in surface areas and volumes

Asked by seeni2005 6th February 2016, 5:35 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

  1. in quad. ABCD . P is the mid pt .of AC . P.T. the ar(ABCD)=ar(BCPD)
  2. ABCD is a parellelogram ,O is a on the side AC. ar(AOB)=ar(AOD).
  3. In cyclic quad.angB-angD 60 deg. ,show that :smaller of those is also 60 d4eg.  

Asked by aninadathoorsridharan 25th January 2016, 7:08 AM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

two paralleograms are on equal bases and between same paralles. the ratio of their areas is 1:1. prove it
 

Asked by rrdave2611 20th March 2015, 9:04 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD is a parallelogram. E is a point on BA such that BE=2FA and F is a point on DC such that DF=2FC. prove that AECF is a parallelogram whose area is one third of the area of parallelogram ABCD.

Asked by manavmansvi 7th March 2015, 11:38 AM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

the side AB of a parallelogram ABCD is produced to any point P. a line through A and parallel to CP meets CB produced at Q and then parellelogram PBQR is completed. show that area ABCD= area PBQR.

Asked by manavmansvi 7th March 2015, 11:25 AM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

In the given figure, M is a point in the interior of a parallelogram PQRS. Show that (i) ar(PMQ) + ar(MRS) = (||gm PQRS) (ii) ar(PMS) + ar(MQR) = ar(PMQ) + ar(MRS)

Asked by Topperlearning User 13th August 2014, 2:57 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

Prove that the parallelograms on the same base and between same parallels are equal in area.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

ABCD is a parallelogram in which CD = 15 cm, its corresponding altitude AM is 8 cm and CN AD. If CN = 10 cm, then find the length of AD.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

In the given figure, ABCD is parallelogram and AE DC. If AB is 20 cm and the area of parallelogram ABCD is 80 cm2, find AE.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that: ar(APB) = ar(BQC)

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

PQRS and ABRS are parallelograms and X is any point on side BR. Show that: (i) area PQRS = area ABRS (ii) area AXS = area PQRS

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

Prove that parallelograms on the same base and between the same parallels are equal in area.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

P is a point in the interior of a parallelogram ABCD. Show that (i) Area APB + Area PCD = area ABCD (ii) Area APD + Area PBC = area APB + area PCD

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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CBSE - IX - Mathematics - Areas of Parallelograms and Triangles

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