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Home /Doubts and Solutions/CBSE/Class 10/Physics/Light Reflection And Refraction

Light Reflection And Refraction Free Doubts and Solutions

CBSE - X - Physics - Light - Reflection and Refraction

Sir sorry to say but I think there's some calculation mistake....the actual answer of magnification is around 3.5

Asked by shamim.ayanahmad 27th December 2017, 9:06 PM
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CBSE - X - Physics - Light - Reflection and Refraction

Real images can only be formed by screen,only concave mirrors form real and enlarged images.then how r we able to ourselves enlarged in certain mirrors??? are these mirrors concave? if they are then how is the image formation possible??pls give me a clear explanation for my query

Asked by my3shyll 29th January 2017, 2:06 PM
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CBSE - X - Physics - Light - Reflection and Refraction

Image formed by a convex mirror of focal length 20cm is one-fourth of the size of the object . Find the distance of the object from the mirror.

Asked by suprakash 20th January 2017, 9:36 PM
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CBSE - X - Physics - Light - Reflection and Refraction

In question 2 , the film slide is the object or image ? please explain this.

Asked by yashpalguglani 22nd November 2016, 7:03 PM
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CBSE - X - Physics - Light - Reflection and Refraction

WHAT IS AN OPTIC FIBRE,AND ITS USES

Asked by afreensyed13 31st October 2016, 7:30 PM
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CBSE - X - Physics - Light - Reflection and Refraction

The magnification produced by a concave mirror is +4D .write the information about the image given by this  statement. 

Asked by sangeeta 7th March 2016, 5:59 PM
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CBSE - X - Physics - Light - Reflection and Refraction

 A person is suffering from myopia as well as hypermetropia. He needs lenses of power -5.5D and +1.5D for  correcting myopia and hypermetropia respective. Find the focal length of the  lenses used by him in spectacle to correct myopia and hypermetropia. 
 

Asked by sangeeta 4th March 2016, 1:11 PM
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CBSE - X - Physics - Light - Reflection and Refraction

What will be the solution of the followinfg question?

Asked by bosesreyan 29th February 2016, 11:00 AM
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