CBSE Class 11-science Answered
Calculate the value of Ka for the following reaction having the equilibrium concentration of H+ 7.1 x 10-5 mol/L in a 0.05 molar solution. H2S 
H+ + HS-
H+ + HS-
Asked by Topperlearning User | 30 Apr, 2015, 11:08: AM
Expert Answer
[H+] = C?
Or, ? = 7.1 x 10-5/ 0.05 = 1.42 x 10-3
Ka = C ?2
= .05 x 1.42 x 10-3 x 1.42x 10-3 = 1.0 x 10-7
Answered by | 30 Apr, 2015, 01:08: PM
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