CBSE Class 11-science Answered

Calculate the pressure of 1 x 10²¹ molecules of nitrogen dioxide when enclosed in a vessel of capacity of 2.5 L capacity at temperature 27ºC?

Asked by Topperlearning User | 20 Apr, 2015, 01:01: PM

Expert Answer

$begin mathsize 11px style Calculation space of space number space of space moles space of space nitrogen space dioxide space equals space fraction numerator 1 space straight x space 10 to the power of 21 over denominator space 6.023 space straight x space 10 to the power of 23 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.166 space straight x space 10 to the power of negative 2 end exponent space mol space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1.66 space straight x space 10 to the power of negative 3 end exponent space mol end style$

Now, PV = nRT

P = ? atm

V = 2.5 L

R = 0.0821 L atm mol^-1 K^-1

T = 27 + 273 = 300 K

n = 1.66 x 10^-3 mol

$begin mathsize 11px style straight P space equals space fraction numerator 1.66 space straight x space 10 to the power of negative 3 end exponent space straight x space 0.0821 space straight x space 300 over denominator 2.5 end fraction end style$