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Calculate the number of grams of glycerol C3H5(OH)3(MW=92.1g/mol) , that must be dissolved in5 520 gm grams of water to raise the boiling point to 102.000c
Asked by s.ojaswini17 | 06 Feb, 2019, 01:59: AM
Expert Answer
Given:
Molecular Weight of glycerol = 92.1 g/mol
We know,
ΔT = m× Kf
Where,
ΔT = 100 - 102
= 2 °C
m = molality of a solution
Weight of glycerol is 184.2 g.
Answered by Varsha | 06 Feb, 2019, 01:05: PM
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