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NEET Class neet Answered

Calculate the normality of 250 mL aqueous solution of H2SO4 having pH -0.0 (a)0.25 N (b)0.50 N (c)1 N (d)2 N
Asked by Balbir | 09 Jul, 2019, 10:25: PM
answered-by-expert Expert Answer
Given:
 
Volume of solution = 250 ml
 
pH of the solution = 0
 
We know,
 
pH = -log[H+]
 
  0 =-log[H+]
 
Taking antilog
 
[H+] = 1 M
 
we know that,
 
Molaity of H2SO4 = 2Normality of H2SO4
 
Normality of H2SO4 
 
 equals space 1 half Molarity space of space straight H subscript 2 SO subscript 4

space equals 1 half cross times 1

equals space 0.5 space straight N
 
Normality of solution is 0.5 N.
 
 
 
Answered by Varsha | 10 Jul, 2019, 10:48: AM
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