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Calculate the normality of 250 mL aqueous solution of H2SO4 having pH -0.0

(a)0.25 N

(b)0.50 N

(c)1 N

(d)2 N

Asked by Balbir 9th July 2019, 10:25 PM
Answered by Expert
Answer:
Given:
 
Volume of solution = 250 ml
 
pH of the solution = 0
 
We know,
 
pH = -log[H+]
 
  0 =-log[H+]
 
Taking antilog
 
[H+] = 1 M
 
we know that,
 
Molaity of H2SO4 = 2Normality of H2SO4
 
Normality of H2SO4 
 
 equals space 1 half Molarity space of space straight H subscript 2 SO subscript 4

space equals 1 half cross times 1

equals space 0.5 space straight N
 
Normality of solution is 0.5 N.
 
 
 
Answered by Expert 10th July 2019, 10:48 AM
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