CBSE Class 10 Answered
Calculate the mass and volume of oxygen required at STP to convert 2.4kg of graphic into carbon dioxide
Asked by Shaikkhajavali1980 | 22 Feb, 2019, 10:12: PM
Expert Answer
C(graphite) + O2 → CO2
Stoichiometric Coeff. 1 1 1
No. Of Moles
According to the reaction Moles of graphite = moles of oxygen required
So X = 54.54 X 32 = 1745.45g = 1.75Kg
And Volume = 54.54 X 22.4 ltrs = 1221.696 L
Answered by Sumit Chakrapani | 24 Feb, 2019, 05:11: AM
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