Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Calculate the mass and volume of oxygen required at STP to convert 2.4kg of graphic into carbon dioxide   
Asked by Shaikkhajavali1980 | 22 Feb, 2019, 10:12: PM
answered-by-expert Expert Answer
C(graphite) + O2CO2
Stoichiometric Coeff. 1 1 1
No. Of Moles 2400 over 44 space equals space 54.54 x over 32
 
According to the reaction Moles of graphite = moles of oxygen required
 
So X = 54.54 X 32 = 1745.45g = 1.75Kg
 
And Volume = 54.54 X 22.4 ltrs = 1221.696 L
Answered by Sumit Chakrapani | 24 Feb, 2019, 05:11: AM

Application Videos

CBSE 10 - Chemistry
Asked by kamalapallysudha17 | 25 Mar, 2024, 07:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Chemistry
Asked by 09.10bjanvhijadhav | 02 Mar, 2024, 08:22: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Chemistry
Asked by prassanna.j | 01 Mar, 2024, 11:59: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Chemistry
Asked by ritik9897022 | 05 Feb, 2024, 09:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Chemistry
Asked by parthmarch1 | 14 Dec, 2023, 08:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Chemistry
Asked by amanazeez6 | 14 Dec, 2023, 01:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Chemistry
Asked by reetritu34 | 14 Dec, 2023, 07:54: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Chemistry
Asked by yadavparmit83 | 01 Dec, 2023, 06:16: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×