CBSE Class 11-science Answered
Calculate the frequency and the wavelength of the radiation in nannometers emmitted when an electron in the hydrogen atom jumps from 3rd orbit to the ground state. In which region of the electromagnetic spectrum will this line lie.
Asked by Keshav sultania | 14 Sep, 2013, 12:48: PM
Expert Answer
Frequency = R ( 1/ n1^2 - 1/ n2 ^2)
Here R is Rydberg Constant = 1.09766 * 10^ 7 m ^-1
n1 = 1 and n2 = 3. We put the values in formula and we get the frequency = 9.75 *10 ^ 6 m^-1
and wavelength = 1/ frequency = 1.02 * 10 ^ -7 meter. The Spectrum will lie in Layman series.
Answered by | 14 Sep, 2013, 09:33: PM
Application Videos
Concept Videos
CBSE 11-science - Chemistry
Asked by ammu32811 | 20 Feb, 2024, 08:58: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by ee7511641 | 13 Jan, 2024, 03:37: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by kv3582976 | 11 Oct, 2023, 06:57: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by o230397 | 23 Sep, 2023, 02:48: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by shrreya27harshitha | 17 Jul, 2022, 04:15: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by habibakhatoon112 | 15 Jul, 2022, 09:14: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by deba.biswas561 | 14 Jun, 2022, 08:07: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by advssdrall | 12 Jan, 2022, 05:12: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by ks1221516 | 14 Nov, 2021, 06:46: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by akankhyapradhan123 | 22 Oct, 2021, 07:29: PM
ANSWERED BY EXPERT