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CBSE Class 12-science Answered

Calculate the freezing point of a solution containing 60 g of glucose (Molar mass = 180g mol-1) in 250 g of water. (Kf of water = 1.86 K kg mol-1)
Asked by raul.chintakindi14 | 14 Mar, 2018, 11:44: AM
answered-by-expert Expert Answer
The freezing point of solution can be calculated as;
 
Given colon

Weight space of space glucose space straight w subscript 2 space equals space 60 space straight g

Weight space of space water space straight w subscript 1 space end subscript space equals space 250 space straight g

Molar space mass space straight M subscript 2 space equals space 180 space gmol to the power of negative 1 end exponent

straight K subscript straight f space of space water space equals space 1.86 space Kkgmol to the power of negative 1 end exponent

We space have comma

increment straight T subscript straight f space equals fraction numerator straight K subscript straight f cross times straight w subscript 2 cross times 1000 over denominator straight M subscript 2 cross times straight w subscript 1 end fraction

space space space space space space space space space equals fraction numerator 1.86 cross times 60 cross times 1000 over denominator 180 cross times 250 end fraction

space space space space space space space space space space space equals 2.48 space

increment straight T subscript straight f space equals straight T to the power of degree subscript straight f space minus straight T subscript straight f

space space space space space space space equals space 273.15 minus space 2.48

therefore straight T subscript straight f space equals 270.67 space straight K

therefore Freezing space point space is space 270 space.60 space straight K space
Answered by Varsha | 14 Mar, 2018, 01:04: PM
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