CBSE Class 11-science Answered
Calculate the dissociation constant of a monobasic acid having the degree of dissociation 2% in its 0.01M solution.
Asked by Topperlearning User | 28 Apr, 2015, 11:01: AM
Expert Answer
Use Ionization constant expression
Substitute the respective values; we get
Ka = (0.01)(0.02 x 0.02)/ (1 - 0.02)
= 4.08 x 10-6 M/L
Answered by | 28 Apr, 2015, 01:01: PM
CBSE 11-science - Chemistry
Asked by sarojlaxmiacharjya | 03 Jan, 2022, 08:50: PM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by cjam41665 | 09 Oct, 2021, 11:11: PM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by rishika62124 | 03 Mar, 2021, 05:02: AM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by jyotijhajharia39 | 06 Jan, 2021, 11:41: PM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by nsaikumar33 | 15 Aug, 2020, 11:50: AM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by swati2678 | 10 Aug, 2020, 01:58: PM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by achamerahul2 | 17 Apr, 2020, 10:50: AM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by achamerahul2 | 17 Apr, 2020, 10:44: AM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by achamerahul2 | 14 Apr, 2020, 02:42: PM
ANSWERED BY EXPERTCBSE 11-science - Chemistry
Asked by SanskarAgarwal86 | 29 Feb, 2020, 04:36: AM
ANSWERED BY EXPERT
