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CBSE Class 11-science Answered

Calculate the approximate number of atoms present in 4.25 of NH³
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Asked by asifiqubalmld | 05 Aug, 2018, 01:05: PM
answered-by-expert Expert Answer
Given:
 
Weight of ammonia = 4.25 g
 
 
Molecular weight of ammonia = 17 
 
 
therefore space No. of space moles space of space ammonia space equals fraction numerator 4.25 over denominator 17 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.25 space mol As space 1 space mole space contains space 6.023 cross times 10 to the power of 23 space molecules 0.25 space mol space will space contain space equals 6.023 cross times 10 to the power of 23 space cross times 0.25 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1.50 cross times 10 to the power of 23 space molecules. As space 1 space molecule space of space NH subscript 3 space equals space 3 space atoms therefore 1.50 cross times 10 to the power of 23 space molecules space of space NH subscript 3 space equals space 1.50 cross times 10 to the power of 23 space cross times 4 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 6.0 space cross times 10 to the power of 23 space atoms space
 
 
4.25 g NH3 will contain 6.0×1023 atoms.
 
Answered by Varsha | 06 Aug, 2018, 10:35: AM

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