CBSE Class 12-science Answered
Calculate the amount of energy released during the decay of
Given :
1.atomic mass of =238.05079u
2. atomic mass of = 234.04363
3.atomic mass of = 4.00260
lu = 931.5 MeV/c2.
Is this decay spontaneous? Give reason.
Asked by Topperlearning User | 09 Jul, 2014, 03:56: PM
Expert Answer
The energy released in the decay is
Q =
= [238.05079 - 234.04363 - 4.00260] x 931.5MeV
= 0.00456 x931.5 = 4.25MeV
As the Q - value is positive, the decay process is spontaneous.
Answered by | 09 Jul, 2014, 05:56: PM
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