CBSE Class 10 Answered
Calculate pH of a solution which contains 9.9 ml of 1 M HCl and 100 ml of 0.1 M NaOH.
Asked by acv27joy | 06 Oct, 2018, 09:21: PM
Expert Answer
The reaction proceeds as :
NaOH + HCl → NaCl + H2O
As we know,
1 mole of HCl reacts with the 1 mole of NaOH
lets find the moles of solution,
Mole HCl in 9.9 ml of 1 M solution =
Mole NaOHin 100 ml of 0.1 M solution =
on mixing the 0.0099 mole of HCl will be neutralised = 0.01 - 0.0099 =
hence, the molarity of NaOH solution =
As we find the molarity lets calculate the pH of solution,
Answered by Ramandeep | 12 Oct, 2018, 12:57: PM
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