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CBSE Class 11-science Answered

CALCULATE NO.OF ATOMS OF EACH TYPE IN 1.8g glocose
Asked by sk77546787 | 17 Aug, 2018, 10:03: PM
answered-by-expert Expert Answer
Given:
 
Weight of glucose=1.8 g
 
molecular space formula space of space glucose colon space straight C subscript 6 straight H subscript 12 straight O subscript 6

Molecular space weight space of space glucose equals 180.15 space straight g divided by mol

No. space of space moles space of space glucose space equals fraction numerator 1.8 over denominator 180.15 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.0099 space moles space of space glucose

1 space mole space of space oxygen space atoms space equals moles space of space glucose space cross times 6 space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.0099 cross times 6

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.0594 space moles space of space oxygen

As space 1 space mole space equals 6.022 cross times 10 to the power of 23 space atoms

0.0594 space moles space of space oxygen space equals 0.0594 space cross times 6.022 cross times 10 to the power of 23 space atoms

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 3.5 cross times 10 to the power of 22 space oxygen space atoms.

For space Carbon space comma

No. space of space carbon space atoms space equals 0.0099 cross times 6 cross times 6.022 cross times 10 to the power of 23

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 3.5 cross times 10 to the power of 22 space carbon space atoms.

For space hydrogen comma

No. space of space hydrogen space atoms space equals 0.0099 cross times 12 cross times 6.022 cross times 10 to the power of 23

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 7.15 cross times 10 to the power of 22 space end exponent hydrogen space atoms
 
In 1.8 g of glucose,
 
No. of carbon atoms =3.5×1022
 
No. of hydrogen atoms =7.15×1022
 
No. of oxygen atoms =3.5×1022
Answered by Varsha | 20 Aug, 2018, 09:59: AM
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