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CBSE Class 12-science Answered

Calcualte the mass of a non volatile solute X that should be dissolved in 180g of water to reduce its vapor pressure to 60% where the molar mass of X is 60g/mol.
Asked by lekhakarthikeyan | 28 Aug, 2018, 06:27: AM
answered-by-expert Expert Answer
Given:
 
w1 = 180 g
 
Vapour pressure of solvent p1° = 60%
 
Vapour space pressure space of space solution space straight p subscript 1 space equals space 60 over 100 cross times straight p subscript 1 to the power of ring operator space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight p subscript 1 space equals space 0.6 straight p subscript 1 to the power of ring operator Mass space of space straight H subscript 2 straight O space straight w subscript 1 space equals space 180 space straight g Molar space mass space of space straight H subscript 2 straight O space straight M subscript 1 space equals space 18 space straight g divided by mol Molar space mass space of space solute space straight M subscript 2 space equals space 60 space straight g divided by mol Mass space of space solute space straight w subscript 2 space equals ? We space have comma fraction numerator straight p subscript 1 to the power of ring operator minus space straight p subscript 1 over denominator straight p subscript 1 to the power of ring operator end fraction space equals space fraction numerator straight w subscript 2 space cross times straight M subscript 1 over denominator straight w subscript 1 cross times straight M subscript 2 end fraction fraction numerator straight p subscript 1 to the power of ring operator minus 0.6 straight p subscript 1 to the power of ring operator over denominator straight p subscript 1 to the power of ring operator end fraction space equals fraction numerator straight w subscript 2 space cross times 18 over denominator 180 cross times 60 end fraction fraction numerator 0.4 straight p subscript 1 to the power of ring operator over denominator straight p subscript 1 to the power of ring operator end fraction equals space fraction numerator straight w subscript 2 space cross times 18 over denominator 180 cross times 60 end fraction 0.4 space equals space fraction numerator straight w subscript 2 space over denominator 600 end fraction straight w subscript 2 space equals 240 space gm
Mass of a non volatile solute is 240 gm
Answered by Varsha | 28 Aug, 2018, 11:31: AM

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